我的示例代码:
import pandas as pd
df = pd.DataFrame({"ID":['1','1','1','2','2'],
"LINE":['1','3','2','1','2'],
"TYPE":['0','1','1','1','0']})
# print results
print(df.head())
# a function to label the first type 1 for each ID sorted by line
# currently it only filters to type 1
def label (row):
if row.TYPE == '1' :
return True
# add the label in the dataframe
df['label'] = df.apply (lambda row: label(row), axis=1)
# print results
print(df.head())
我想为每个按LINE
排序的唯一ID
获得TYPE == 1
的第一个匹配项。最终结果应该是:
ID LINE TYPE label
0 1 1 0 None
1 1 3 1 None
2 1 2 1 True
3 2 1 1 True
4 2 2 0 None
我在这个问题中使用了一个示例,但实际上我正在处理300万个数据行,我想知道执行此操作的最有效方法。
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